Question

(a)
In transferring 4.5 C charge through a wire, 27 J of work is
needed. Find the potential difference across the wire.
[2]​

Answer 1

$\LARGE{ \underline{\underline{ \red{ \bf{Required \: answer:}}}}}$

GiveN:

• Electric charge carried = 4.5 C
• Work done = 27 J

To FinD:

• The potential difference across the wire?

Step-wise-Step Explanation:

Potential difference between any two points is defined as the world done in carrying a unit test charge from one point to another. It is given by:

$\large{ \boxed{ \rm{V_{diff.} = \frac{W}{q} }}}$

Where,

• Vdiff. is the potential difference between two points.
• W is the work done.
• q is the charge carried.

Putting the values in the formula,

⇒ Vdiff. = 27 J / 4.5 C

⇒ Vdiff. = 6 J/C

The other name of the unit J/C is known as Volt. Hence, the potential difference between across the wire is 6 V .

Answer 2

Answer:

$\huge \bf \: question$

In transferring 4.5 C charge through a wire, 27 J of work is needed. Find the potential difference across the wire.

$\huge \bf \: given$

• Transferring charge through wire - 4.5 C
• Work needed = 27 Joule (J)

$\huge \bf \: to \: find$

Potential difference across the wire

$\huge \bf \: solution$

$potential \: difference \: = \frac{work \: done}{charge}$

$potential \: energy \: = \frac{27}{4.5}$

$\: potential \: energy \: difference \: = 6 \: volt$