Question

a iron wire is 24 cm long is formed into a rectangle, if the width of to is rectangle is 5 cm , what is its length ?​

Answer 1

Answer:

36 square units

Step-by-step explanation:

36 square units.

Let width = w

2x + 2w = 24

2w = 24 - 2x

w = 12 - x

A = xw

A = (x)(12-x) = 12x - x ^2

dA/dx = 12 -2x = 0 at max area.

12 = 2x

6 = x

A =(6)(12–6) = 36

If you realize that the max area rectangle is always a square, it is easier:

side = 6, A = 6 squared = 36, simple as that.

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Answer 2

Answer:

$Perimeter =sum \: of \: all \: sides=24 cm$

$Perimeter \: of \: rectangle = 2(l + b)$

$24 = 2(l + 5)cm$

$24 \div 2 = l + 5$

$12 = l + 5$

$12 - 5 = l$

$l = 7$

Step-by-step explanation:

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