Question

A is 2 years older than B. B is twice as old as C. If the sum of ages A, B, and C is 27 years, what will be the age of B?


6 years. 8 years.
9 years. 10 years ​

Answer 1

Answer:

10 years.

Explanation:

Given that,

A is 2 years older than B

B is twice old as C.

Sum of the ages of A, B, and C is 27 years.

Find the age of B

Step 1 : Let's assume the age of

• C as $x$ years.

Therefore, we can say that

B's age is twice as $x$

Or, $2x$ years.

And also,

A's age is $2x + 2$ years.

Step 2 : Find the age of C

The sum of the ages of

A + B + C = 27 years.

${ \underline \boldsymbol{According \: to \: the \: question : }}$

$\implies (2x + 2) + 2x + x = 27$

$\implies 2x + 2 + 2x + x = 27$

$\implies 5x + 2 = 27$

$\implies 5x = 27 - 2$

$\implies 5x = 25$

$\implies x = \dfrac{25}{5}$

$\implies x = 5$

${\therefore{ \underline{ \sf {\: C's\: age \: is \: 5 \: years }}}}$

Step 3 : Calculate B's age

Since, B is twice the age of C

B's age will be : $2x = \bf 2(5) = 10 \: years.$

Answer 2

Answer:

10 years.

Explanation:

Given that,

A is 2 years older than B

B is twice old as C.

Sum of the ages of A, B, and C is 27 years.

Find the age of B

Step 1 : Let's assume the age of

C as x years.

Therefore, we can say that

B's age is twice as x

Or, 2x years.

And also,

A's age is 2x +2 years.

Step 2 : Find the age of C

The sum of the ages of

A + B + C = 27 years.

${ \underline \boldsymbol{According \: to \: the \: question : }}$

$\begin{gathered}\implies (2x + 2) + 2x + x = 27 \\\end{gathered}$

$\begin{gathered}\implies 2x + 2 + 2x + x = 27 \\\end{gathered}$

$\implies 5x + 2 = 27$

$\begin{gathered}\implies 5x = 27 - 2 \\\end{gathered}$

$\begin{gathered}\implies 5x = 25 \\\end{gathered}$

$\begin{gathered}\implies x = \dfrac{25}{5} \\\end{gathered}$

$\implies x = 5$

$\begin{gathered}{\therefore{ \underline{ \sf {\: C's\: age \: is \: 5 \: years }}}} \\\end{gathered}$

Step 3 : Calculate B's age

Since, B is twice the age of C

B's age will be : 2x = $\bf 2(5) = 10 \: years.$