Question

A is 2 years younger than B, who is twice as old as C. if the total of the ages of A, B and C is 28 years, then how old is B?​

Answer 1

let B age be x

A be x + 2

C be 2x

• x + x+2 + 2x = 28
• 4x + 2 = 28
• 4x = 28 - 2
• 4x = 24
• x = 24 / 4
• x = 6

Then , age of B is 6 year .

Answer 2

Answer:

Let us consider the A as 'x'

let B be '2x'

let C be '4x'

The total ages of A,B and C are 28 years

X + 2x + 4x = 28

7x = 28

X = 28/7

X = 4

Therefore 2x = 2×4 = 8

Since 4x = 4×4 = 16

Therefore the age of A is 4 years

and the age of B is 8 years

and the age of C is 16 years

Explanation:

If we consider A as 'x'

then the B is 2 year older than A

so B is '2x'

and same the C is twice as old as B

so C is (2x × 2) = 4x