Question

A is 4 times as old as B. 10 years ago , A was 10 times as old as B. find the present age of B.​

Answer 1

Step-by-step explanation:

Let B be x years old

Now:

B=x

A=4x

Ten years ago

B=x-10

A=4x-10

Ten years ago,A was 4 times as old as B

4x-10=10(x-10)

4x-10=10x-100

-10+100=10x-4x

90=6x

x=90/6

x=22.5