A is 5 years elder than B. Ten years ago, A’s age was double than B’s age. Then present ages of A and B are
Answers
Given :
- A is 5 years elder than B.
- Ten years ago, A’s age was double than B’s age.
To find :
- Present ages of A and B =?
Step-by-step explanation :
Let the present age of B's be, x.
Then, the present age of A's be, x + 5.
10 years ago, A was four times B’s age. [Given]
Now,
10 years ago their ages were B’s age = x - 10
10 years ago their ages were A’s age, x + 5 - 10 = x - 5.
According to the question,
x - 5 = 2(x + 10)
x - 5 = 2x + 20
x - 2x = 20 + 5
x = 25.
Therefore, We got the value of, x = 25.
Hence,
The present age of B's, x = 25 years.
Then, the present age of A's, x + 5 = 25 + 5 = 30 years.
Answer:
The present ages of A and B are 30 years and 25 years.
Given :
➛A is 5 years elder than B.
➛Ten years ago, A’s age was double than B’s age.
To find :
Present ages of A and B.
Solution:
We are given,
➛A is 5 years elder than B.
➛Ten years ago, A’s age was double than B’s age.
Let the present age of B be, m.
According to given condition,
➺The present age of A's be, m + 5.
10 years ago, A was four times B’s age. [Given]
Now,
➺10 years ago their ages were B’s age = m - 10
➺Therefore, 10 years ago their ages were A’s age, m + 5 - 10 = m - 5.
➪m - 5 = 2(m + 10)
➪m - 5 = 2m + 20
➪m - 2m = 20 + 5
➪m = 25.
Hence,
The present age of B is , m = 25 years.
Then, the present age of A is, m + 5 =
25 + 5 = 30 years.