Question

form the differential equation by eliminating arbitrary constants z=ax+a^2y^2+b

Answer 1

The partial differential form of the equation is given as q =2$p^2y$

Given:

Differential equation by eliminating arbitrary constants z=ax+a^2y^2+b

To Find:

The partial differential equation of the form

Solution:

Consider the equation,

Which has an arbitrary constants,

z=ax+a^2y^2+b

Differentiate the equation partially with respect to x

We get,

P = $\frac{dz}{dx}$

Differentiate the equation partially with respect to y,

We get,

q = 2$p^2y$

Eliminating the constants between a ,

The results will show as,

q = 2 $p^2y$

Hence, we get the equation which is of partial differentia equation is,

q = 2 $p^2y$

#SPJ1