Question

A is 5 years older than B. Five years ago, A was twice as old as B. Find their present ages.

Answer 1

Let age of B = x
Therefore age of A = x +5

Five years ago age of B = x-5

Five years ago age of = (x+5) - 5
= x

ATQ
X = 2 (x-5)

x = 2x - 10

x-2x = -10

-x = - 10

x = 10

Therefore present age of B = 10
Present age of A = 10+5
= 15

Answer 2

Answer:Let age of B = x

Therefore age of A = x +5

Five years ago age of B = x-5

Five years ago age of = (x+5) - 5

= x

ATQ

X = 2 (x-5)

x = 2x - 10

x-2x = -10

-x = - 10

x = 10

Therefore present age of B = 10

Present age of A = 10+5

= 15