Question

A is 50% more efficient than B. C
does half of the work done by A & B
together. If C alone do the work in 40
days. In how many days all will finish
the same work together?
A. 10/3
B. 20/3
C. 30
D. 40/3​

Answer 1

In $\frac{40}{3}$ days all will finish the same work together.

Step-by-step explanation:

Given that C alone do the work in 40 days.

Work done by C in one day = $\frac{1}{40}$

C does half of the work done by A & B together =

$C=\frac{1}{(A+B)2}$

$\frac{1}{40}=\frac{1}{(A+B)2}$

$\frac{2}{40}=\frac{1}{(A+B)}$

$\frac{1}{(A+B)}=\frac{1}{20}$

A and B together can do the work in 20 days.

Now A, B and C together  can do the work =

$\frac{1}{20}+\frac{1}{40}$

= $\frac{2+1}{40}$

= $\frac{3}{40}$   [Inverse the fraction]

= $\frac{40}{3}$ days

In $\frac{40}{3}$ days all will finish the same work together.

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