Question

A is 8 years younger than B, and 24 years older than C, one sixth of A's age, half of B's and one third of c's together amount to 38 years. find their ages​

Answer 1

Answer:

Age of

A= 34 years

B= 42 years

C= 10years

Step-by-step explanation:

let age of A, B &C be a, b & respectively.

According to question

a + 8 = b

a - 24 = c

now,

$\frac{a}{6} + \frac{b}{2} + \frac{c}{3} = 38$

$\frac{a + 3b + 2c}{6} = 38$

$a + 3(a + 8) + 2(a - 24) = 38 \times 6$

$a + 3a + 24 + 2a - 48 = 228$

$6a - 24 = 228$

$6a = 204$

$a = 34$

$b = a + 8 = 34 + 8 = 42$

$c = a - 24 = 34 - 24 = 10$

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