Question

A is a 3x3 matrix and |A|=2then|adj(adj(adjA)) |=

Answer 1

Answer:

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Answer 2

Answer:

Consider the following identity A(adjA)=∣A∣I. Thus comparing it with the above equation gives us ∣A∣=10

Now ∣adjA∣=∣A∣

n−1

where n is the order of the square matrix.

Here 'n' is 3, therefore, ∣adjA∣=∣A∣

3−1

=∣A∣

2

=10

2

=100.