A is at(−5,5)and B is at (3,7)P is a point on y-axis which is equidistant from A and B. What are the coordinates of P
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Answer:
Given ap =bp
then
let p' s coordinats are x and y
✓(x+5)^2+(y-5)^2 = ✓(x-3)^2+(y-7)^2
after taking both side square
x^2+25+10x+y^2+25-10y=x^2+9-6x+y^2+49-14y
16x+4y=8
then
given p is situated at y axis
x=0
y=2
then the coordinate of point p =(0,2)
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