Question

a3+b3+3ab2+3a2b if a=2. b=-3

Answer 1

Answer:

-1

Step-by-step explanation:

$a^{3}  + b^{3} + 3ab^{2} + 3a^{2}b$ is the given equation.

here it directly gives us the identity

$(a+b)^{3}$ = $a^{3}  + b^{3} + 3ab^{2} + 3a^{2}b$

so, we can put a = 2 and b = -3 in identity  $(a+b)^{3}$  directly.

Substituting the values, we get LHS as

$(2+(-3))^{3}$

$(-1)^{3}$

= -1