∠a is complementary to ∠c. If ∠a=2x−10 and ∠c=4x+40, find the ∡a and ∡c.
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Step-by-step explanation:
angles a+c=90°(since they are complementary)
so,
2x-10+4x+40=90°
6x+30=90°
6x=90-30
6x=60
x=60/6
x=10
substituting the value of x as 10, we get:
angle a=2x-10
=2(10)-10
=20-10
a=10°
angle c=4x+40
=4(10)+40
=40+40
c=80°
therefore angle a=10° and angle c=80°
a+c=90°
thus verified.
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