A is now 9 years older than B. in 10 years A will be twice as old as B was 10 years ago .find their present ages .
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Answered by
71
Let,
the age of B = x
the age of A = 9 + x
according to the question,
(10 + (9 + x) ) = 2( x-10)
(19 + x) = 2x - 20
19 + 20 = 2x - x
39 = x
B's age = 39
A's age = 9+ 39 = 48
the age of B = x
the age of A = 9 + x
according to the question,
(10 + (9 + x) ) = 2( x-10)
(19 + x) = 2x - 20
19 + 20 = 2x - x
39 = x
B's age = 39
A's age = 9+ 39 = 48
Answered by
22
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