A is older to B by 2 years. A's father F is twice as old as A and B as twice as old his sister S. If the age of the father and sister differ by 40 years, find the age of A
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A=B+2
F=2A
B=2S
Now,A=2S+2
F=2(2S+2)
F=4S+4
Given that,
F-S=40
4S+4-S=40
3S=40-4
3S=36
S=12
A=2S+2
A=2(12)+2
A=24+2
A=26
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F=2A
B=2S
Now,A=2S+2
F=2(2S+2)
F=4S+4
Given that,
F-S=40
4S+4-S=40
3S=40-4
3S=36
S=12
A=2S+2
A=2(12)+2
A=24+2
A=26
Please mark my answer as Brainliest
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