Question

A is six times as old as



b. 15 years hence a will be three times old as



b.Find the ages of a and b

Answer 1

Answer:

$a= 6b ............(1)\\ 3a + 45 = 6b + 15.............(2) \\ from(1) \\ 3(6b) + 45 = 6b + 15 \\ 18b + 45 = 6b + 15 \\ 12b = - 30 \\ b= \frac{ - 30}{12} = \frac{ - 5}{2} \\ from(1) \\ a = 6( \frac{ - 5}{2} ) = - 15$

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Answer 2

Answer:

Step-by-step explanation:

A-60

B-10