A is thrice as efficient as B and hence complete a work in 40 days less than the number of days taken by b.what is the number of days taken by both of then when work together
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work of B in 1 hr be X
work of A in 1hr is 3X
![no \: days \: taken \: by \: b = \frac{1}{x} \\ \: no \: days \: taken \: by \: a = \frac{1}{3x} no \: days \: taken \: by \: b = \frac{1}{x} \\ \: no \: days \: taken \: by \: a = \frac{1}{3x}](https://tex.z-dn.net/?f=no+%5C%3A+days+%5C%3A+taken+%5C%3A+by+%5C%3A+b+%3D+%5Cfrac%7B1%7D%7Bx%7D+%5C%5C+%5C%3A+no+%5C%3A+days+%5C%3A+taken+%5C%3A+by+%5C%3A+a+%3D+%5Cfrac%7B1%7D%7B3x%7D+)
![\frac{1}{x} - \frac{1}{3x} = \frac{3 - 1}{3x} = \frac{2}{3x} \frac{1}{x} - \frac{1}{3x} = \frac{3 - 1}{3x} = \frac{2}{3x}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7Bx%7D+-+%5Cfrac%7B1%7D%7B3x%7D+%3D+%5Cfrac%7B3+-+1%7D%7B3x%7D+%3D+%5Cfrac%7B2%7D%7B3x%7D+)
![\frac{2}{3x} = 40 \\ x = \frac{2}{3 \times 40} = \frac{1}{60} \frac{2}{3x} = 40 \\ x = \frac{2}{3 \times 40} = \frac{1}{60}](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B3x%7D+%3D+40+%5C%5C+x+%3D+%5Cfrac%7B2%7D%7B3+%5Ctimes+40%7D+%3D+%5Cfrac%7B1%7D%7B60%7D+)
3x=(1/20)
total work done in 1 hr =(1/20)+(1/60)=(3+1)/60
=2/60
=1/30
no of days taken when whorking togeather=30
work of A in 1hr is 3X
3x=(1/20)
total work done in 1 hr =(1/20)+(1/60)=(3+1)/60
=2/60
=1/30
no of days taken when whorking togeather=30
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