A is thrice fast as B if B can do a piece of work in 24 days then find the number of place they will take to complete the work together
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Together they will take 6 days.
• Given data :
A can finish the total job in thrice faster speed than B.
B can finish the total job into 24 days.
• So,the number of days A will take to complete the total job is
= 24/3
= 8 days
• Let,the total amount of work = 1 (Assume 1 as a variable to do the further mathematical calculations)
• So,
In 8 days A does = 1 work
In 1 day A does = 1/8 work
• And,
In 24 days B does = 1 work
In 1 day B does = 1/24 work
• So,In 1 day A+B will complete = (1/8+1/24) = (3+1/24) = 4/24 = 1/6 work
• Now,together
They complete 1/6 work in = 1 day
They complete 1 work in = 1×6 = 6 days
Together,they will finish the total job in 6 days (answer).
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