Question

A is twice as a good workman as B and together they complete a work in 15 days . In how many days can the work be completed by B alone
...........................................................................................PLZZZZ HELP

Answer 1

Answer:

Let B be x and A be 2x

(A+B)'s 18 days' work=1

(A+B)'s 1 days' work=1/18

This can also be written as

x+2x=1/18

3x=1/18

x=1/54

Let's multiply both sides of this equation by 2.

Therefore,

2x=1/27=>A's 1 day's work=1/27

Thus, A alone can do a piece of work in 27 days.