Question

A is twice as B. Five years ago A was 3 times as old as B. Find their present ages.

Answer 1

hey, mate here is ur Ans

Let the present age of A's be=x
and age of B's be=y

now, according to question
x=2y...... equation 1

five years ago
(x-5)3=(y-5)

3x-y=5..... equation 2

now put value of x in equation 2 to find their present ages
x=2 and y=1