Math, asked by javedmannan12, 8 months ago

A is twice as good a workman as b and together they finish a piece of work in 14 days. A alone can finish the work in ?Solution

Answers

Answered by bhagyashreechowdhury
3

A alone can finish the work in 21 days if A and B can finish a piece of work in 14 days.

Step-by-step explanation:

It is given that,

A is twice as good a workman as B i.e., A is twice as efficient as B.

Since Efficiency ∝ [1/(Time Taken)]

So, let’s assume that the time taken by A to do a piece of work be “x” days then B will take “2x” days to do the same piece of work.

Therefore,

Work done by A in 1 day = \frac{1}{x}

And

Work done by B in 1 day = \frac{1}{2x}

Also given that, A & B together can do a piece of work in 14 days.

So, work done by A&B in 1 day = \frac{1}{14}

Now, we can write the eq. as,

\frac{1}{x}  + \frac{1}{2x}  = \frac{1}{14}

⇒ [2x + x] / [2x²] = \frac{1}{14}  

⇒ 3x / [2x²] = \frac{1}{14}

⇒ 3 * 14 = 2x

⇒ x = 3 * 7

x = 21 days

Thus, A alone can finish the work in 21 days.

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