Question

A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many will A alone finish the work?

Answer 1

HEY FRIEND HERE YOUR ANSWER

Let B be x and A be 2x

(A+B)'s 18 days' work=1

(A+B)'s 1 days' work=1/18

This can also be written as

x+2x=1/18

3x=1/18

x=1/54

Let's multiply both sides of this equation by 2.

Therefore,

2x=1/27=>A's 1 day's work=1/27

Thus, A alone can do a piece of work in 27 days.

I HOPE IT'S HELP YOU

MARK BRAINLIEST MY ANSWER DEAR FRIEND

THANKS.......

Answer 2

Answer:

21 days

Step-by-step explanation:

1/X + 1/2X = 1/14

2+1/2X = 1/14

3X= 1/7

X = 3*7

X=21 days