A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many will A alone finish the work?
shubhamray03:
pls answer it fast
Answers
Answered by
111
HEY FRIEND HERE YOUR ANSWER
Let B be x and A be 2x
(A+B)'s 18 days' work=1
(A+B)'s 1 days' work=1/18
This can also be written as
x+2x=1/18
3x=1/18
x=1/54
Let's multiply both sides of this equation by 2.
Therefore,
2x=1/27=>A's 1 day's work=1/27
Thus, A alone can do a piece of work in 27 days.
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS.......
Let B be x and A be 2x
(A+B)'s 18 days' work=1
(A+B)'s 1 days' work=1/18
This can also be written as
x+2x=1/18
3x=1/18
x=1/54
Let's multiply both sides of this equation by 2.
Therefore,
2x=1/27=>A's 1 day's work=1/27
Thus, A alone can do a piece of work in 27 days.
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS.......
Answered by
8
Answer:
21 days
Step-by-step explanation:
1/X + 1/2X = 1/14
2+1/2X = 1/14
3X= 1/7
X = 3*7
X=21 days
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