A is twice as good as a workman as B and together they finish a piece of work in 18 days . in how many days will be alone finish the work .
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A is twice of B
let B be x
then A is 2x
2x+x=18
3x=18
x=18÷3
x=6
A =2x
=2×6
= 12 days
B=x
=6 days
let B be x
then A is 2x
2x+x=18
3x=18
x=18÷3
x=6
A =2x
=2×6
= 12 days
B=x
=6 days
Shivgupta07:
answer is 27
A's one day work is asked
u first check the question
it can never be 27 days i challenge u
challenge accepted brother
are u sure
means u are telling that A's time is 27 days
??
have u checked my answer
Let A:B = 2:1, A's 1 day work is (2/3)*(1/18). Ans 27
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2
check this out . Don't forget to thanks
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yes checked your answer. please refer to my answer in the above answer's comment section.
ohhk
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