A is twice as good as a workman as B and together they finish a piece of work in 18 days . in how many days will be alone finish the work .
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A is twice of B
let B be x
then A is 2x
2x+x=18
3x=18
x=18÷3
x=6
A =2x
=2×6
= 12 days
B=x
=6 days
let B be x
then A is 2x
2x+x=18
3x=18
x=18÷3
x=6
A =2x
=2×6
= 12 days
B=x
=6 days
Shivgupta07:
answer is 27
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