Math, asked by Shivgupta07, 1 year ago

A is twice as good as a workman as B and together they finish a piece of work in 18 days . in how many days will be alone finish the work .

Answers

Answered by DOMINOSTAR
5
A is twice of B
let B be x
then A is 2x

2x+x=18
3x=18
x=18÷3
x=6

A =2x
=2×6
= 12 days
B=x
=6 days

Shivgupta07: answer is 27
Shivgupta07: A's one day work is asked
kuldeep108: u first check the question
kuldeep108: it can never be 27 days i challenge u
Shivgupta07: challenge accepted brother
kuldeep108: are u sure
kuldeep108: means u are telling that A's time is 27 days
kuldeep108: ??
kuldeep108: have u checked my answer
Shivgupta07: Let A:B = 2:1, A's 1 day work is (2/3)*(1/18). Ans 27
Answered by kuldeep108
2
check this out . Don't forget to thanks
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Shivgupta07: yes checked your answer. please refer to my answer in the above answer's comment section.
kuldeep108: ohhk
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