Question

A is twice as old as B. Ten years ago, he is 4 times old as B. What are their present age?

Answer 1

Answer:

Let B be X

     A be 2x

Ten years ago

B was x-10

A was 2x-10

but in the question they have said that 4(x-10) is equal to 2x-10

∴ATS

2x-10=4(x-10)

2x-10=4x-40

2x-4x=-40+10

-2x=-30

x=-30/-2

x=15

so the present ages are

A=2x

 =2x15

 =30

B=x

 =15

please mark as brainliest answer

Step-by-step explanation: