Question

area of rectangle is 25a²-35a+12 then the dimensions are​

Answer 1

Answer

Given that the area of the rectangle is of the form 25a² -35a+12

To find:

The dimensions of the rectangle

•Factors of the equation would be the length and breadth of the rectangle

Factorizing,

25a²-35a+12=0

→25a²-20a-15a+12=0

→5a(5a-4)-3(5a-4)=0

→(5a-4)(5a-3)=0

→5a-4=0 or 5a-3=0

→a=4/5 or 3/5

The length and breadth could be 4/5 units and 3/5 units