Question

A is twice as old as B. Ten years ago he was four times as old as B. What are their
ages?​

Answer 1

Step-by-step explanation:

Let B's age be x years. Then A's age is 2x years.

Ten years ago, their ages were, respectively, x-10 and 2x -10 years. Thus, we have

2x−10=4(x−10)

or 2x−10=4x−40

or 2x=30

∴x=15

So, B is 15 years old and A is 30 years old.

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