A is twice as old as b three years ago a was three times as old b was find their present ages
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Answered by
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Answer:
Consider B’s present age as x years. So age of A is 2x years. 3 years ago, B’s age was (x-3) years, and A’s age was (2x-3)years. The equation for the age relation 3 years ago is,
3 B’s age = A’s age.
So, 3(x-3)= 2x -3.
3x-9 = 2x - 3.
x = 6.
So, B’s age is 6 years. And as A is twice as old as B at present. Therefore, A’s present age is 12 years.
Answered by
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Answer:
A’s present age is 12 years, B’s age is 6 years.
Step-by-step explanation:
Let x = A’s current age
Let y = B’s current age
x = 2y [A is twice as old as B]
x-3 = 3 (y-3) [3 years ago A was 3 times as old as B]
If we replace x with 2y the equation above becomes:
2y-3 = 3(y-3)
2y-3 = 3y -9
6 = y
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Hope it helps you!
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