Math, asked by zulfiqarzulfi286, 8 months ago

A is twice as old as b three years ago a was three times as old b was find their present ages​

Answers

Answered by salvebhanu
0

Answer:

Consider B’s present age as x years. So age of A is 2x years. 3 years ago, B’s age was (x-3) years, and A’s age was (2x-3)years. The equation for the age relation 3 years ago is,

3 B’s age = A’s age.

So, 3(x-3)= 2x -3.

3x-9 = 2x - 3.

x = 6.

So, B’s age is 6 years. And as A is twice as old as B at present. Therefore, A’s present age is 12 years.

Answered by avaneedesai11
0

Answer:

A’s present age is 12 years, B’s age is 6 years.

Step-by-step explanation:

Let x = A’s current age

Let y = B’s current age

x = 2y [A is twice as old as B]

x-3 = 3 (y-3) [3 years ago A was 3 times as old as B]

If we replace x with 2y the equation above becomes:

2y-3 = 3(y-3)

2y-3 = 3y -9

6 = y

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Hope it helps you!

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