A is twice old as b two years ago,if the difference between the age is 2 years find a's ae
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let present age of A&B is X&Y respectively
two years ago----
x-2 =2( y-2)
x-2=2y-4
x-2y=-2-----------(1)
difference b/w age
x-y=2-----------(2)
San(2)-eqn(1)
y=4
putting in eqn(2)
x=6
two years ago----
x-2 =2( y-2)
x-2=2y-4
x-2y=-2-----------(1)
difference b/w age
x-y=2-----------(2)
San(2)-eqn(1)
y=4
putting in eqn(2)
x=6
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