find the roots 2/5x²-x-3/5=0
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first multiply with 5 on both sides and find the roots by using the formula
-b+/-sqrt(b^2-4ac)/2a
-b+/-sqrt(b^2-4ac)/2a
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Answered by
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2x² / 5 - x/1 - 3/5 = 0
By Taking LCM ,
2x² - 5x - 3 = 5* 0
2 x² - 5x - 3 = 0
By Prime factorisation { (2x²) * (-3)= -6x² , also -6x ² = - 6x * 1 x , and -6x + 1x = -5x }
2 x² - 6x + 1 x + 3 = 0
2x ( x -3 ) +1 ( x + 3 ) = 0
(2x+1 ) ( x - 3 ) = 0
2x + 1 = 0 or x -3 = 0
x = - 1 / 2 or x = 3
x = - 1 / 2 and 3 are ROOTS of above quadratic equation.
By Taking LCM ,
2x² - 5x - 3 = 5* 0
2 x² - 5x - 3 = 0
By Prime factorisation { (2x²) * (-3)= -6x² , also -6x ² = - 6x * 1 x , and -6x + 1x = -5x }
2 x² - 6x + 1 x + 3 = 0
2x ( x -3 ) +1 ( x + 3 ) = 0
(2x+1 ) ( x - 3 ) = 0
2x + 1 = 0 or x -3 = 0
x = - 1 / 2 or x = 3
x = - 1 / 2 and 3 are ROOTS of above quadratic equation.
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