Question

A is two times more efficient than b. If they complete a work in30 days, find the time required by each to complete the work individually. A) a- 40 days b- 120 days b) a- 120 days b- 40 days c) a- 20 days b- 60 days d) a- 30 days b- 60 days

Answer 1

Let’s solve it using a simple method that involves simple calculations that can be computed in brain itself.

Let B do 1 unit of work per day.

So, A will do 1 + 1 * 3 = 4 units of work per day because he is 3 times more efficient than B.

So together they do 1 + 4 =5 units in 1 day.

So when they work for 30 days they will do 30*5 = 150 units of work.

So total work is 150 units.

Time taken by B alone is 150/1 = 150 days.

( efficiency of B is 1 unit/day)

Time taken by A alone is 150/4 = 37.5 days

(efficiency of A is 4 units/day)

Answer 2

Answer:

Step-by-step explanation:

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