Question

a is two years older than B B is 3 years older than c and the sum of their ages is half the age of dip at the end of the 10 years time the sum of the ages of A B and C will be equal to the age of D find the present age​

Answer 1

Let, the age of c be x

age of b =  x+3

age of a = x+3+2

              = x+5

So, the age of d= (x+x+3+x+5)*2

                          = (3x+8)*2

                          = 6x+16

By condition,

6x+16 = (x+10)+(x+3+10)+(x+5+10)

or, 6x + 16 = 3x+38

or, 6x-3x = 38-16

or, 3x = 22

or, x = (22/3)

or, x = 7 years+(12*1/3) months

or, x = 7 years 4 months

So, the age of  c is 7 years 4 months

The age of  b = (7+3) years 4 months

                      = 10 years 4 months

The age of a = (10+2) years 4 months

                     = 12 years 4 months

The age of d = {(12+10+7) years + (4+4+4)/12 years}*2 years

                     = (29 + 1 years) * 2 years

                     = (30*2) years

                     = 60 years.