Math, asked by BandyopadhyayRick, 1 year ago

A is younger than B by 7 years and older than C by 6 years.Sum of 2/3 age of A's and 3/5 of B and 3/4 of C is 36 years.What is the Age of A?

Answers

Answered by abhi569
2

Answer:

Age of A is 18 years.


Step-by-step explanation:

Let the present age of A be "a" years,

So,

Present age of B = ( a + 7 ) years

Present age of C = ( a - 6 ) years


It is given in the question that the sum of 2/3 age of A's and 3/5 of B and 3/4 of C is 36 years.


According to the question : -

⇒ 2 / 3 of A's age + 3 / 5 of B's age + 3 / 4 of C's age = 36 years

= >  ( 2 / 3 x a years ) + { 3 / 5 x ( a + 7 ) years } + { 3 / 4 x ( a - 6 ) years } = 36 years

= >  2a / 3 + { 3( a + 7 )} / 5 + { 3( a - 6 ) } / 4 = 36

= >  2a / 3 + ( 3a + 21 ) / 5 + ( 3a - 18 ) / 4 = 36

= >  { 20( 2a ) + 12( 3a + 21 ) + 15( 3a - 18 ) } / 60 = 36

= >  40a + 36a + 252 + 45a - 270 = 2160

= >  121a - 18 = 2160

= >  121 a = 2160 + 18

= >  121 a = 2178

= >  a = 2178 / 121

= >  a = 18


Therefore the age of A is 18 years, age of B is ( a + 7 = 18 + 7 = 25 ) 25 years and the age of C is ( a - 6 = 18 - 6 = 12 ) 12 years.

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