Physics, asked by Naitik3834, 9 months ago

A jar 40 m deep is full of full of liquid with density of 1.3g/cm3. At what depth below the surface of the liquid is the pressure equal to the pressure exerted by a column of mercury? Density of mercury 13.6 g/cm3, g = 9.8 m/s/s

Answers

Answered by jasmeetvirklic2007
0

Answer:

I cannot understand this question

Answered by shaibumuhammed246
0

Answer:

Explanation:

pressure[p] exerted at the commom level of mercury C is the same in both lmbs.

therefore, p=hip1g=h2p2g.

p2g/pig=h2/h1

where p2=density of mercury 13.6

p1=density of water 1.3

g=9.8m/s2

h1=5cm=5/100=0.05m

h2=?

p2g/p1g=h2/h1

h2=p2gh1/p1g

13.6*0.05*9.8/1.3*9.8

6.664/12.74=0.523

=0.5m

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