A jar 40 m deep is full of full of liquid with density of 1.3g/cm3. At what depth below the surface of the liquid is the pressure equal to the pressure exerted by a column of mercury? Density of mercury 13.6 g/cm3, g = 9.8 m/s/s
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Explanation:
pressure[p] exerted at the commom level of mercury C is the same in both lmbs.
therefore, p=hip1g=h2p2g.
p2g/pig=h2/h1
where p2=density of mercury 13.6
p1=density of water 1.3
g=9.8m/s2
h1=5cm=5/100=0.05m
h2=?
p2g/p1g=h2/h1
h2=p2gh1/p1g
13.6*0.05*9.8/1.3*9.8
6.664/12.74=0.523
=0.5m
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