Question

a jar contained a mixture of two liquids A and B in the ratio 4:1 when 10 liter of the mixtures was taken out and 10 liters of liquids B was poured into the jar this ratio became 2:3 the quantity of liquid A contained in the jar intially was ​

Answer 1

Let the volume of the initial total mixture was V. When 10L of mixture is removed the volume becomes (V - 10). The concentration stays 4:1.

Next step, when you add 10 litres of B, the amount of A does not change.

So

Amount of A in original mix = Amount of A in final mix

C1 * V1 = C2 * V2

(4/5)*(V - 10) = (2/5)*V

1 - 10/V = 1/2

V = 20

So volume of A in initial mixture was (4/5) * 20 = 16 litres

Answer (C)

Answer 2

Here is ur answer buddy