A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now
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Final quantity of alcohol in the mixture = 700700+175∗(90100)2∗[700+175] = 567 ml
Therefore, final quantity of water in the mixture = 875 - 567 = 308 ml
Hence, we can say that the percentage of water in the mixture = 308875×100 = 35.2 %
Therefore, final quantity of water in the mixture = 875 - 567 = 308 ml
Hence, we can say that the percentage of water in the mixture = 308875×100 = 35.2 %
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