Question

A jar contains mixture of rum and vodka in the ratio of 4:1 ,when 10 l of mixture taken out and same amount of vodka poured into jar the ratio becomes 2:3 then find how many liters of rum was contained in jar initially?

Answer 1

new ratio
(a-8)/(b-2+10) = 2/3
gives 3a-2b = 40.

a/b old ratio = 4:1

3*(4x) -2 *(x) = 40 gives
x=4
thus
a = 4*4 = 16.

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