A jeep is moving at the rate of 72 km/ph.On applying brakes ,it comes to rest in a distance of 200m. Calucalate the retardation produced and time taken
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S= u2 / 2a
so...
200= 400/2a
so...
a= 1m/s^2
therefore retardation produced is 1m/s^2...
Hope it helps!!!
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