Question

a jeep is travelling at 40 m/s when the breaks are applied. it comes to a stop after 20 seconds. find:
a. acceleration
b. distance traveled after the breaks are applied.

Answer 1

Here is your answer
I hope you understand it.

Answer 2

a.) Acceleration = -2 m/s²

b.) Distance traveled = 400 m

Step-by-step Explanation:

Given: Initial Velocity u = 40 m/s

Time taken by the car to stop = 20 s

Final Velocity v = 0 m/s

To Find: Acceleration and Distance traveled

Solution:

• Finding the acceleration

Using the first equation of motion, i.e. v = u + at, we can find the acceleration.

⇒ v = u + at

⇒ 0 = 40 + a × 20

⇒ 20a = -40

⇒ a = -2 m/s²

• Finding the distance traveled

Using the third equation of motion, i.e. 2as = v² - u², we can find the distance traveled.

⇒ 2as = v² - u²

⇒ 2 × (-2) × s = (0)² - (40)²

⇒ 4s = 1600

⇒ s = 400 m

Hence, (a) the acceleration is -2 m/s² and (b) the distance traveled is 400 m