A jeep starts from rest and attains a speed of 40 km in 10
minutes. The uniform acceleration will be
(1) 4kmh
(2) 4km m-1
(3) 66.7 ms 2
(4) 66.7 ms-
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Step-by-step explanation:
soln,
given,
intial velocity (u)=0m/sec
final velocity (v)=40km
time taken(t)=10 minutes=10×60sec=600sec
Now,
acceleration (a)=v-u/t
=40-0/600
=66.7ms 2
I hope it will help you...
and thanks for giving this opportunity to help....
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