Physics, asked by pujakhalate2020, 1 month ago

A jet of water hits a partition wall 6m. Away at a height of 4m. Above ground, i.e. above the discharging point. When the partition wall moved 2m, further away. The hit it again at the same point on the wall. Determine the angle at which the jet was projected assume that the curve described is a parabola.​

Answers

Answered by manishadhiman31
0

Answer:

Correct option is

C

182

The ball passes through the point P(4, 4). Also rang = 4 + 14 = 18 m.

The trajectory of the ball is,

y=xtanθ(1−Rx)

Now x = 4m, y = 4m and R = 18 m

∴4=4tanθ[1−184]=4tanθ97

or tanθ=79 ⇒ θ=tan−179 And R=g2u2sinθcosθ

or 18=9.82×u2×1309×1307⇒u=182

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