A jet of water hits a partition wall 6m. Away at a height of 4m. Above ground, i.e. above the discharging point. When the partition wall moved 2m, further away. The hit it again at the same point on the wall. Determine the angle at which the jet was projected assume that the curve described is a parabola.
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182

The ball passes through the point P(4, 4). Also rang = 4 + 14 = 18 m.
The trajectory of the ball is,
y=xtanθ(1−Rx)
Now x = 4m, y = 4m and R = 18 m
∴4=4tanθ[1−184]=4tanθ97
or tanθ=79 ⇒ θ=tan−179 And R=g2u2sinθcosθ
or 18=9.82×u2×1309×1307⇒u=182
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