a jet of water issuing horizontally out of an orifice 10sq. cm in area with the velocity of 20cm/s strikes a vertical wall. Assuming that the water falls vertically downward without splashing after impact, what is the force exerted by the jet on the wall
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assuming that the water falls vertical wall assuming that the water falls.
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volume of water coming out of the pipe = A * v
= 20 cm² * 10 m/sec
= 0.02 m³/sec
mass of water hitting the wall = m = 0.02 m³/sec * 1000 kg/m³
= 20 kg/sec
As the water hits the wall normal to the wall and gets rebounded at the same speed, the change of momentum of water hitting the wall is:
= m (v - (-v)) = 2 m v
= 2 * 20 kg /sec * 10 m/sec
= 400 kg-m/sec²
Since, the change of momentum obtained is per unit time, it is same as the force. Thus the force acting on the wall by water = force experienced by water jet.
= 400 Newtons.
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