Question

A jet plane is moving vertically upward with speed 300 kilometre per hour it is rejecting product of combustion with speed 1200 kilometre per hour with respect to find out actual product of combustion.​

Answer 1

Answer:

900 km per hour

Explanation:

Given

Speed of moving jet plane = 300 kilometre per hour

Speed of ejection product combustion = 1200 kilometre per hour with respect to itself

A.T.Q.

=> Vr = Vj + VP

=> 1200 = 300 + Vp

=> Vp = 900 km/ h

Hence

Speed of combustion product is 900 km per hour.

Answer 2

A jet is moving vertically upward with speed = 300km/hr.

Rejecting product of combustion with speed = 1200km/hr.

Vr = Vj + VP

1200 = 300 + Vp

Vp = 1200-300 = 900

Vp = 900 km/hr.

So, actual product of combustion = 900km/hr.

hope it helps...