Question

A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.​

Answer 1

Answer:-

• 1837.5m
• 105m/s

Explanation:-

Given :

Initial velocity (u) = 0m/s

Time taken (t) = 35s

To find :

Distance (s)

Final velocity (v)

Formula used:

• S = ut + 1/2 × at²
• v = u + at

Solution :

S = 0(35) + 1/2 × 3(35)²

S = 0 + 1/2 × 3(1225)

S = 0 + 1/2 × 3675

∴ S = 1837.5 meters

v = u + at

v = 0 + 3(35)

∴ v = 105 m/s