a jet plane travelling at the speed of 500 km per hour eject its products of combustion at the speed of 1500 km per hour relative to the jet plane what is the speed of the the latter with respect to an observer on the ground
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Relative velocity
V A/B = v A−v B
given
V A/B = 1500Km/h
v A − v B =1500
v A − (−500)=1500
Since the velocity of combustion products and plane are in opposite directions
V A = 1000km/h
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Answer:
3 hour in 1500 km per hour relative
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