Question

a jio stationary satellite is orbiting the earth at a hieght of 5R surface of the earth where R is the reading of earth hence fine the time period of another satellite at a hieght of 2R from the surface of earth.

Answer 1

h = altitude of the satellite above the surface of EArth.
we know that      mv²/(R+h) = GMm/(R+h)²    --- (1)
                           T = 2 π (R+h) / v       --(2)

Solving them, we get   T² = (4π²/GM)  (R+h)³
T = 24 hrs  for Geostationary orbit,  h = 5 R

So    T² / 24² = (R+ 2R)³ / (R + 5R)³ = 1/8
         T = 6√2  Hours