A job can be completed by a person a alone in 24 days and by another person b alone in 40 days. a and b work on the job together and c works with them for 6 days. the three complete the job in 12 days. in how many days can c alone complete the job?
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A can complete 1 work in 24 days.
B can complete 1 work in 40 days.
A can complete 1/24 work in 1 day.
B can complete 1/40 work in 1 day.
Work done by A+B in 1 day = 1/24 +1/40 = 5+3/120 = 8/120 = 1/15
Work done by A+B in 12 days = 1/15*12 = 12/15 = 4/5
Therefore, the work left is = 1-4/5 = 1/5
The work done by C in 6 days is = 1/5
Work done by C in 1 day = (1/5)/6 = 1/30
Therefore C can complete 1/30 work in 1 day.
C can complete 1 work in 30 days.
C can complete the job in alone in 30 days.
Hope it helps.
Thank you
B can complete 1 work in 40 days.
A can complete 1/24 work in 1 day.
B can complete 1/40 work in 1 day.
Work done by A+B in 1 day = 1/24 +1/40 = 5+3/120 = 8/120 = 1/15
Work done by A+B in 12 days = 1/15*12 = 12/15 = 4/5
Therefore, the work left is = 1-4/5 = 1/5
The work done by C in 6 days is = 1/5
Work done by C in 1 day = (1/5)/6 = 1/30
Therefore C can complete 1/30 work in 1 day.
C can complete 1 work in 30 days.
C can complete the job in alone in 30 days.
Hope it helps.
Thank you
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