A job can be done by A in 5 days, B in 10 days and L in 15 days. A and B got up to 2 working days
If B is touched after doing so, how many days will it take for A and C to do the rest of the work?
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one day work of A= 1/5
one day work of A= 1/5one day work of B= 1/10
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15Now, all three A,B and C work together for 2 days.
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15Now, all three A,B and C work together for 2 days.hence, 2 day work of A,B and C is 2(1/5 + 1/10 + 1/15)
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15Now, all three A,B and C work together for 2 days.hence, 2 day work of A,B and C is 2(1/5 + 1/10 + 1/15)and is equal to 55/75
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15Now, all three A,B and C work together for 2 days.hence, 2 day work of A,B and C is 2(1/5 + 1/10 + 1/15)and is equal to 55/75Now remaining work = 1- 55/75 = 20/75 have to completed by only C as A and B left the work
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15Now, all three A,B and C work together for 2 days.hence, 2 day work of A,B and C is 2(1/5 + 1/10 + 1/15)and is equal to 55/75Now remaining work = 1- 55/75 = 20/75 have to completed by only C as A and B left the workaccording to question, C can complete whole work in 15 days
one day work of A= 1/5one day work of B= 1/10one day work of C= 1/15Now, all three A,B and C work together for 2 days.hence, 2 day work of A,B and C is 2(1/5 + 1/10 + 1/15)and is equal to 55/75Now remaining work = 1- 55/75 = 20/75 have to completed by only C as A and B left the workaccording to question, C can complete whole work in 15 dayshence to complete 20/75 work C needs 15*20/75 = 4 Days
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