Question

A particle discribes a circle of radius 'r' what are the displacement and distance travelled when the particle decribe 90°

Answer 1

Answer:

1. Distance travelled by the particle

$= \frac{ {90}^{0} }{ {360}^{0} } \times(2\pi \: r)$

$= \frac{1}{4} \times (2\pi \: r)$

$= \frac{\pi \: r}{2}$

2. Displacement of particle

= straight line distance between final and initial point

$= \sqrt{ {r}^{2} + {r}^{2} }$

$= \sqrt{2 {r}^{2} }$

$= \sqrt{2} r$