Question

a Jogger jogs along one length and breadth of a rectangular park.if the dimensions of park are 150m ×120m find the distance and the displacement of the Jogger

Answer 1

Howdy!!!

your answer is -----

jogger jogs along one length and breadth of rectangular park .

Given, L => 150 and B = 120m

so, Distance travel by jogger is

150+120 = 270 m

and for Displacement

we draw diagonal of park and then using Pythagoras theorem -

Displacement =
$\sqrt{ {150}^{2} + {120}^{2} } \\ = \sqrt{36900} = 30 \sqrt{41} meter$

hope it help you